# 2023 AoC Day 2 – Cube Conundrum

This is a solution to Advent of Code 2023 day 2, written in Raku.

### Part One

Determine which games would have been possible if the bag had been loaded with only 12 red cubes, 13 green cubes, and 14 blue cubes. What is the sum of the IDs of those games?

my ($r,$g, $b) = 12, 13, 14; my$total = 0;

outer:
for '2-input.txt'.IO.lines {
my ($game,$plays) = .split(': ');
$game =$game.split(' ')[1];
my @plays = $plays.split('; ' )>>.comb(/\d+|\w+/ )>>.map(->$n, $c {$c => $n } )>>.Bag; for @plays ->$p {
next outer if $p<red> >$r or $p<green> >$g or $p<blue> >$b;
}
$total +=$game;
}
say "Sum of game ids is {$total}"; Sum of game ids is 2505  ### Part Two For each game, find the minimum set of cubes that must have been present. What is the sum of the power of these sets? my$total = 0;

for '2-input.txt'.IO.lines {
my ($game,$plays) = .split(': ');
$game =$game.split(' ')[1];
my @plays = $plays.split('; ' )>>.comb(/\d+|\w+/ )>>.map(->$n, $c {$c => $n } )>>.Bag; my$r = @plays.map(-> $p {$p<red> }).max;
my $g = @plays.map(->$p { $p<green> }).max; my$b = @plays.map(-> $p {$p<blue> }).max;

$total +=$r * $g *$b;
}
say "Sum of powers is {\$total}";
Sum of powers is 70265